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Case Study RC2 - Optimized Reliability Allocation

Software Used: 
BlockSim 7

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In this example, a system is defined using subdiagrams. A reliability target is set for the entire system and reliability is then allocated to the subsystems, assemblies and components using an optimized allocation methodology.

Consider the following system composed of two subsystems, A and B, as shown below:

System RBD

Subsystem A is composed of two assemblies, A and B. Assembly B is in a 2-out-of-3 redundant configuration.

Subsystem A RBD

Subsystem B is composed of two assemblies, C and D. 

Subsystem B RBD

Assembly A is made up of components 0 and 1.

Assembly A RBD

Assembly B is made up of components 3, 4 and 5.

 Assembly B RBD

Assembly C is made up of components 6 and 7.

Assembly C RBD

Assembly D is made up of components 8 and 9.

 Assembly D RBD

Furthermore, assume the following life characteristics for each component:

Component

Life (Failure) Distribution

Comp. 0 : Weibull Beta = 2 Eta = 5,000
Comp. 1 : Weibull Beta = 2 Eta = 4,500
Comp. 3 : Weibull Beta = 1.5 Eta = 8,965
Comp. 4 : Weibull Beta = 1 Eta = 8000
Comp. 5 : Lognormal Log Mean = 10 Log Sigma = 1.4
Comp. 6 : Weibull Beta = 3 Eta = 10,000
Comp. 7 : Weibull Beta = 3 Eta = 6,000
Comp. 8 : Exponential Mean = 10,000  
Comp. 9 : Weibull Beta = 2.2 Eta = 7,000

The system reliability for this configuration at 500 hr is R(t) = 0.925656. Let's assume that the target reliability for this system is R(t = 500) = 0.95.

Determine an optimum reliability allocation strategy assuming that the cost/difficulty of increasing an item's reliability is defined by the following function. 

equation     (1)

Where:

  • () is the penalty (or cost) function as a function of component reliability.

  • f is the feasibility (or cost index) of improving a component's reliability relative to the other components in the system.

  • $R_{min,i}$ is the current reliability at the time at which the optimization is to be performed.

  • $R_{max,i}$ is the maximum achievable reliability at the time at which the optimization is to be performed.

At the system level, we'll set Subsystem 1 to f = 0.9 and Subsystems 2 to f = 0.7. Rmax for both subsystems is 0.99999 at 500 hrs.

Then the optimum allocation scheme for each subsystem is the one that satisfies:

equation

While minimizing:

equation

Solving this yields an optimum allocation for each subsystem. Specifically, the new target reliability for Subsystem A is 0.986137 and for Subsystem B is 0.963344.

Figure 1      [Enlarge]

Figure 1: Click to Enlarge

The process can then be repeated for each assembly and component in the system. The results are given in the next table. 

Table of Results

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